JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts..

**Q1.**With a concave mirror, an object is placed at a distance x_1 from the principal focus, on the principal axis. The image is formed at a distance x_2 from the principal focus. The focal length of the mirror is

**Q2.**Two lenses shown are illuminated by a beam of parallel light from the left. Lens B is then moved slowly toward lens A. The beam emerging from lens B is

**Q3.**A biconvex lens of focal length fforms a circular image of radius rof sun in focal plane. Then which option is correct?

Solution

r=ftanÎ¸ Or r∝f ∴ Ï€r^2∝f^2

r=ftanÎ¸ Or r∝f ∴ Ï€r^2∝f^2

**Q4.**Two thin symmetrical lenses of different nature and of different material have equal radii of curvature R=15 cm. The lenses are put close together and immersed in water (Î¼_w=4/3). The focal length of the system in water is 30 cm. The difference between refractive indices of the two lenses is

**Q5.**One of the refracting surfaces of a prism of angle 30° is silvered. A ray of light incident at angle of 60° retraces its path. The refractive index of the material of prism is

**Q6.**A spherical convex surface separates object and image spaces of refractive indices 1.0 and 4/3. If radius of curvature of the surface is 10 cm, find its power

**Q7.**A concave lens forms the image of an object such that the distance between the object and image is 10 cm and the magnification produced is 1/4. The focal length of the lens will be

Solution

Concave lens forms the virtual image of a real object. So, let u=-4x and v=-x Then, 3x=10 cm Or x=10/3cm ∴ u=-40/3 cm and v=-10/3 cm Subtracting in 1/f=(-3)/10+3/40 Or f=-40/9 Or f=-4.4 cm

Concave lens forms the virtual image of a real object. So, let u=-4x and v=-x Then, 3x=10 cm Or x=10/3cm ∴ u=-40/3 cm and v=-10/3 cm Subtracting in 1/f=(-3)/10+3/40 Or f=-40/9 Or f=-4.4 cm

**Q8.**Critical angle of glass is Î¸_1 and that of water is Î¸_2. The critical angle for water and glass surface would be (Î¼_g=3/2,Î¼_w=4/3)

**Q9.**A biconvex lens of focal length 15 cm is in front of a plane mirror. The distance between the lens and the mirror is 10 cm. A small object is kept at a distance of 30 cm from the lens. The final image is

**Q10.**When an object is placed 15 cm from a lens, a virtual image is formed. Mark the correct statements

Solution

Both the lenses (convex or concave) form virtual image of a real extended object. In both the cases, image would be erect For convex lens, virtual image will form when object is in-between focus and optical center For concave lens, virtual image will form for any location of object, and corresponding image is lying between focus and optical center

Both the lenses (convex or concave) form virtual image of a real extended object. In both the cases, image would be erect For convex lens, virtual image will form when object is in-between focus and optical center For concave lens, virtual image will form for any location of object, and corresponding image is lying between focus and optical center